{"id":3420,"date":"2013-03-11T19:57:25","date_gmt":"2013-03-11T18:57:25","guid":{"rendered":"http:\/\/www.tugtowing.cz\/?p=3420"},"modified":"2013-03-12T20:39:49","modified_gmt":"2013-03-12T19:39:49","slug":"skola-plavby-5-dil-pristavaci-manevr","status":"publish","type":"post","link":"https:\/\/www.tugtowing.cz\/?p=3420","title":{"rendered":"\u0160kola plavby – 5.d\u00edl – p\u0159ist\u00e1vac\u00ed man\u00e9vr"},"content":{"rendered":"

\"009\"<\/a>Snad \u017e\u00e1dn\u00fd man\u00e9vr nen\u00ed tak z\u00e1ludn\u00fd jako tento. V\u011bt\u0161inou b\u00fdv\u00e1 za\u0159azen na konec sout\u011b\u017en\u00ed plavby. N\u011bkdy se vyskytne i b\u011bhem plavby. M\u00e1te za sebou n\u011bkolik dlouh\u00fdch minut pln\u00e9ho soust\u0159ed\u011bn\u00ed. \u00dasp\u011b\u0161n\u011b jste zvl\u00e1dli proplout celou tra\u0165 a zb\u00fdv\u00e1 mali\u010dkost – \u00fasp\u011b\u0161n\u011b p\u0159ist\u00e1t. Man\u00e9vr p\u0159i kter\u00e9m m\u016f\u017eete hodn\u011b z\u00edskat, ale taky hodn\u011b ztratit. B\u011bhem p\u0159ist\u00e1n\u00ed tak\u00e9 nej\u010dast\u011bji kapit\u00e1ny popadne „p\u00e1\u010dkov\u00fd b\u011bs“<\/em> a kdy\u017e se „zada\u0159\u00ed“<\/em>, nest\u00edh\u00e1 rozhod\u010d\u00ed zapisovat trestn\u00e9 body \ud83d\ude42<\/p>\n

P\u0159ist\u00e1vac\u00ed man\u00e9vr m\u00e1 svoje specifika. Zpravidla man\u00e9vrujete ve st\u00edsn\u011bn\u00e9m prostoru p\u0159\u00edstavn\u00edho baz\u00e9nu. Vlek m\u00e1 minim\u00e1ln\u00ed rychlost a mus\u00edme je zastavit \u00fapln\u011b ve vyzna\u010den\u00e9m prostoru. Jakmile vlek zastav\u00edte, obt\u00ed\u017en\u011b jej zase rozpohybujete. Nav\u00edc jeden z remork\u00e9r\u016f \u010dasto nad vlekem ztr\u00e1c\u00ed kontrolu. Je pot\u0159eba si d\u00e1vat dobr\u00fd pozor na setrva\u010dnost vleku. Lze ji dob\u0159e vyu\u017e\u00edt, ale na druhou stranu m\u016f\u017ee v\u00fdrazn\u011b znep\u0159\u00edjemnit cel\u00fd man\u00e9vr a to nebudeme uva\u017eovat pov\u011btrnostn\u00ed vlivy. Zkr\u00e1tka do hry vstupuje hodn\u011b negativn\u00edch faktor\u016f, se kter\u00fdmi se mus\u00edte \u00fasp\u011b\u0161n\u011b vypo\u0159\u00e1dat.<\/p>\n

Prvn\u00ed a snad nejd\u016fle\u017eit\u011bj\u0161\u00edm podm\u00ednkou<\/strong> pro \u00fasp\u011b\u0161n\u00e9 p\u0159ist\u00e1n\u00ed je, \u017ee se oba kapit\u00e1ni p\u0159edem dohodnou<\/strong> jak\u00fdm zp\u016fsobem s vlekem p\u0159istanou a b\u011bhem man\u00e9vru spolu neust\u00e1le komunikuj\u00ed. I ty nejsehran\u011bj\u0161\u00ed t\u00fdmy se p\u0159edem domlouvaj\u00ed. Bez p\u0159edchoz\u00ed domluvy p\u0159ist\u00e1n\u00ed ani rad\u011bji nezkou\u0161ejte.<\/p>\n

Druhou podm\u00ednkou<\/strong> je, \u017ee vlek V maj\u00ed oba remork\u00e9ry pln\u011b pod kontrolu. Soulod\u00ed nen\u00ed rozh\u00e1zen\u00e9, vlek se nekontrolovan\u011b neto\u010d\u00ed apod. Pokud m\u00e1te dost \u010dasu je v\u00fdhodn\u011bj\u0161\u00ed si na p\u0159ist\u00e1vac\u00ed man\u00e9vr l\u00e9pe nebo opakovan\u011b najet, ne\u017e se pokusit o p\u0159ist\u00e1n\u00ed z prvn\u00edho chodu.<\/p>\n

T\u0159et\u00ed podm\u00ednkou<\/strong> je, \u017ee m\u00e1te neust\u00e1le na pam\u011bti, \u017ee i sebemen\u0161\u00ed popota\u017een\u00ed vle\u010dn\u00e9ho lana se ihned projev\u00ed na dr\u00e1ze a rychlosti V<\/strong>. \u010c\u00edm pomaleji V<\/strong> pluje, t\u00edm je projev takov\u00e9ho „\u0161kubnut\u00ed“<\/em> v\u00fdrazn\u011bj\u0161\u00ed. Z toho vypl\u00fdv\u00e1, \u017ee je pot\u0159eba zvolit spr\u00e1vnou d\u00e9lku vle\u010dn\u00fdch lan.<\/p>\n

Jak p\u0159ist\u00e1vac\u00ed man\u00e9vr provedete, z\u00e1le\u017e\u00ed na tvaru p\u0159\u00edstavn\u00edho baz\u00e9nu a um\u00edst\u011bn\u00ed prostoru kam a jak mus\u00edme vlek zakotvit. N\u011bkdy projektant nechal m\u00edsta v\u00edce, jindy st\u011b\u017e\u00ed pro vlek V<\/strong>. No a samoz\u0159ejm\u011b tak\u00e9 na man\u00e9vrovac\u00edch schopnostech va\u0161ich remork\u00e9r\u016f a jak je dok\u00e1\u017eete vyu\u017e\u00edt.<\/p>\n

P\u0159ist\u00e1n\u00ed prvn\u00ed – p\u0159\u00edstavn\u00ed molo<\/strong><\/p>\n

M\u00edsto p\u0159ist\u00e1n\u00ed nen\u00ed nikterak omezeno. Vyzna\u010den\u00fd je pouze prostor do kter\u00e9ho je pot\u0159eba um\u00edstit vlek. Zd\u00e1nliv\u011b se jedn\u00e1 o relativn\u011b jednoduch\u00fd man\u00e9vr. P\u0159i p\u0159ibl\u00ed\u017een\u00ed k p\u0159\u00edstavn\u00edmu molu, R1<\/strong> za\u010dne sni\u017eovat tah a sou\u010dasn\u011b R2<\/strong> brzd\u00ed V. K m\u00edstu p\u0159ist\u00e1n\u00ed se m\u016f\u017eeme p\u0159ibli\u017eovat rovnob\u011b\u017en\u011b s molem a nebo pod m\u00edrn\u00fdm \u00fahlem.<\/p>\n

P\u0159i rovnob\u011b\u017en\u00e9m p\u0159ibl\u00ed\u017een\u00ed R1<\/strong> povol\u00ed vle\u010dn\u00e9 lano (v\u00fdrazn\u00e9 sn\u00ed\u017een\u00ed tahu) a nech\u00e1 V<\/strong> plout setrva\u010dnost\u00ed pod kontrolou R2<\/strong>. Ihned potom provede obrat, aby se p\u0159\u00edd\u00ed dostal kolmo k boku V<\/strong>. Man\u00e9vr mus\u00ed prov\u00e9st opatrn\u011b aby ne\u0161kubnul za vle\u010dn\u00e9 lano a t\u00edm V<\/strong> nevych\u00fdlil ze sm\u011bru. V p\u0159\u00edpad\u011b, \u017ee nem\u00e1 dostate\u010dn\u011b dlouh\u00e9 vle\u010dn\u00e9 lano, m\u016f\u017ee se postavit k boku V<\/strong> kolmo z\u00e1d\u00ed. R2<\/strong> sni\u017euje rychlost plavby V<\/strong> a\u017e k jeho \u00fapln\u00e9mu zastaven\u00ed. Zastaven\u00ed mus\u00ed b\u00fdt provedeno p\u0159esn\u011b aby V<\/strong> celou d\u00e9lkou trupu byl mezi zna\u010dkami pro p\u0159ist\u00e1n\u00ed. R2<\/strong> vypluje p\u0159\u00edd\u00ed kolmo k boku V<\/strong>. Potom sou\u010dasn\u011b R1<\/strong> a R2<\/strong> p\u0159itla\u010d\u00ed V<\/strong> k p\u0159\u00edstavn\u00edmu molu. P\u0159ira\u017een\u00ed mus\u00ed prob\u011bhnout perfektn\u011b synchronizovan\u00e9, aby V<\/strong> z\u016fstal rovnob\u011b\u017en\u00fd s p\u0159\u00edstavn\u00edm molem. Je t\u0159eba si uv\u011bdomit, \u017ee v tomto okam\u017eiku je velice obt\u00ed\u017en\u00e9 V<\/strong> zastavit, pop\u0159. vr\u00e1tit zp\u011bt. Pokud se netref\u00edte mezi p\u0159ist\u00e1vac\u00ed zna\u010dky, p\u0159irazte vlek i tak. Po p\u0159ira\u017een\u00ed jeden z remork\u00e9r\u016f bude p\u0159idr\u017eovat V<\/strong> u p\u0159\u00edstavn\u00edho mola a druh\u00fd remork\u00e9r opatrn\u011b provede korekci polohy V<\/strong> mezi zna\u010dky. P\u0159ibrzd\u011bn\u00ed p\u0159i tomto man\u00e9vru provede remork\u00e9r, kter\u00fd V<\/strong> udr\u017euje u p\u0159\u00edstavn\u00edho mola tak, \u017ee zv\u00fd\u0161\u00ed v\u00fdkon a V<\/strong> v\u00edc p\u0159itiskne k p\u0159\u00edstavn\u00edmu molu.<\/p>\n

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Pokud se p\u0159ibli\u017eujeme pod m\u00edrn\u00fdm \u00fahlem, p\u0159\u00ed\u010f V<\/strong> by m\u011bla sm\u011b\u0159ovat ke vzd\u00e1len\u011bj\u0161\u00ed zna\u010dce, zhruba 1\/4 \u0161\u00ed\u0159ky m\u00edsta p\u0159ist\u00e1n\u00ed p\u0159ed ni. R1<\/strong> provede p\u0159ed p\u0159\u00edstavn\u00edm molem obrat tak, aby se p\u0159\u00edd\u00ed nebo z\u00e1d\u00ed dostal kolmo k boku V<\/strong> a p\u0159iraz\u00ed p\u0159\u00ed\u010f V<\/strong> k p\u0159\u00edstavn\u00edmu molu. M\u016f\u017ee vyu\u017e\u00edt setrva\u010dnosti V<\/strong> a nechat jej sklouznout po p\u0159\u00edstavn\u00edm molu aby se p\u0159\u00ed\u010f dostala t\u011bsn\u011b p\u0159ed p\u0159ist\u00e1vac\u00ed zna\u010dku. T\u00edm vlek zabrzd\u00ed.\u00a0 Ve stejn\u00e9m okam\u017eiku R2<\/strong> V prakticky zastav\u00ed a provede man\u00e9vr, kter\u00fdm se p\u0159\u00edd\u00ed dostane kolmo k boku V<\/strong> a p\u0159iraz\u00ed V<\/strong> k p\u0159\u00edstavn\u00edmu molu. R1<\/strong> neust\u00e1le p\u0159idr\u017euje p\u0159\u00ed\u010f V<\/strong> u p\u0159\u00edstavn\u00edho mola! V\u00fdhodou tohoto man\u00e9vru je v\u011bt\u0161\u00ed p\u0159esnost a fakt, \u017ee V<\/strong> m\u00e1me pod kontrolou prakticky po celou dobu man\u00e9vru.<\/p>\n

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V t\u00e9to situaci, kdy m\u00e1me pro man\u00e9vry obou remork\u00e9r\u016f dostatek prostoru, bychom b\u011bhem p\u0159ist\u00e1n\u00ed nem\u011bli ud\u011blat chybu. Jedin\u00fdm mo\u017en\u00fdm \u00faskal\u00ed je dotyk n\u011bkter\u00e9ho remork\u00e9ru o p\u0159ist\u00e1vac\u00ed molo, kter\u00e9 nen\u00ed podle pravidel povoleno. Daleko zaj\u00edmav\u011bj\u0161\u00ed a n\u00e1ro\u010dn\u011bj\u0161\u00ed je p\u0159ist\u00e1n\u00ed do p\u0159\u00edstavn\u00edho baz\u00e9nu, kde p\u0159\u00edstavn\u00ed hr\u00e1ze v\u00fdrazn\u011b omezuj\u00ed man\u00e9vrovac\u00ed prostor.<\/p>\n

\"59\"<\/a> \"61\"<\/a><\/p>\n

P\u0159ist\u00e1n\u00ed druh\u00e9 – otev\u0159en\u00fd p\u0159\u00edstavn\u00ed baz\u00e9n<\/strong><\/p>\n

P\u0159\u00edstavn\u00ed baz\u00e9n m\u00e1 zpravidla obd\u00e9ln\u00edkov\u00fd tvar, kdy jedna strana je po cel\u00e9 d\u00e9lce otev\u0159en\u00e1 pro vplut\u00ed soulod\u00ed a zpravidla p\u0159ist\u00e1n\u00ed mus\u00ed prob\u011bhnout k prot\u011bj\u0161\u00ed stran\u011b. Po stran\u00e1ch jsou p\u0159\u00edstavn\u00ed hr\u00e1ze. I u tohoto typu p\u0159\u00edstavu m\u016f\u017eeme p\u0159ist\u00e1vat dv\u011bma zp\u016fsoby, kter\u00e9 jsou stejn\u00e9 jako v p\u0159edchoz\u00edm p\u0159\u00edpad\u011b.<\/p>\n

Pokud se rozhodneme p\u0159ist\u00e1t zp\u016fsobem, kdy p\u0159ibl\u00ed\u017een\u00ed provedeme rovnob\u011b\u017en\u011b<\/strong> s p\u0159\u00edstavn\u00edm molem, je pot\u0159eba po\u010d\u00edtat s t\u00edm, \u017ee \u010d\u00edm bude p\u0159\u00edstav u\u017e\u0161\u00ed a p\u0159\u00edstavn\u00ed hr\u00e1ze del\u0161\u00ed, t\u00edm bude tento man\u00e9vr obt\u00ed\u017en\u011bj\u0161\u00ed! P\u0159i p\u016fsoben\u00ed v\u011btru nebo vodn\u00edho proudu nebude provediteln\u00fd prakticky v\u016fbec.<\/p>\n

Proto je lep\u0161\u00ed do takov\u00e9ho p\u0159\u00edstavu vplouvat v\u017edy \u0161ikmo<\/strong> k p\u0159\u00edstavn\u00edmu molu. Pod jak\u00fdm \u00fahlem m\u016f\u017eeme vplout do p\u0159\u00edstavn\u00edho baz\u00e9nu ur\u010duje d\u00e9lka p\u0159\u00edstavn\u00edch hr\u00e1z\u00ed. \u010c\u00edm jsou hr\u00e1ze krat\u0161\u00ed, t\u00edm m\u016f\u017ee b\u00fdt \u00fahel vplut\u00ed men\u0161\u00ed. S d\u00e9lkou p\u0159\u00edstavn\u00edch hr\u00e1z\u00ed se zv\u011bt\u0161uje i \u00fahel vplouv\u00e1n\u00ed a\u017e m\u016f\u017ee b\u00fdt skoro kolm\u00fd.<\/p>\n

Pro oba zp\u016fsoby p\u0159ibl\u00ed\u017een\u00ed plat\u00ed stejn\u00fd postup jako u prvn\u00edho p\u0159ist\u00e1n\u00ed jen s t\u00edm rozd\u00edlem, \u017ee remork\u00e9ry se mus\u00ed vyh\u00fdbat nejen p\u0159\u00edstavn\u00edmu molu, ale i p\u0159\u00edstavn\u00edm hr\u00e1z\u00edm. Oba kapit\u00e1ni tak p\u0159i sv\u00fdch man\u00e9vrech mus\u00edm myslet na to, aby se s remork\u00e9rem nedostali mezi V<\/strong> a p\u0159\u00edstavn\u00ed molo. Tak\u00e9 je velice nep\u0159\u00edjemn\u00e9, kdy\u017e v\u00e1m zbude velmi m\u00e1lo man\u00e9vrovac\u00edho prostoru k proveden\u00ed obratu. Je pot\u0159eba man\u00e9vry prom\u00fd\u0161let dop\u0159edu a v\u010das o nich informovat sv\u00e9ho par\u0165\u00e1ka!<\/strong><\/p>\n

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P\u0159ist\u00e1n\u00ed t\u0159et\u00ed – p\u0159\u00edstavn\u00ed baz\u00e9n s vjezdem<\/strong><\/p>\n

Zde mus\u00edme rozli\u0161ovat kde je vjezd do p\u0159\u00edstavn\u00edho baz\u00e9nu um\u00edst\u011bn\u00fd. Uva\u017eujeme op\u011bt situaci, kdy p\u0159\u00edstavn\u00ed baz\u00e9n m\u00e1 obd\u00e9ln\u00edkov\u00fd tvar. Vjezd m\u016f\u017ee b\u00fdt protilehl\u00fd (v\u016f\u010di p\u0159ist\u00e1vac\u00edmu molu) s posunem ke stran\u011b a nebo bo\u010dn\u00ed. U t\u011bchto p\u0159\u00edstavn\u00edch baz\u00e9n\u016f tak prakticky odpad\u00e1 mo\u017enost rovnob\u011b\u017en\u00e9ho p\u0159ibl\u00ed\u017een\u00ed a p\u0159ira\u017een\u00ed V ob\u011bma remork\u00e9ry najednou. To je mo\u017en\u00e9 jen v p\u0159\u00edpad\u011b, \u017ee bo\u010dn\u00ed vjezd je hned u p\u0159ist\u00e1vac\u00edho mola. Podle toho kde se nach\u00e1z\u00ed vjezd lze prov\u00e9st jednu \u010di dv\u011b varianty p\u0159ist\u00e1vac\u00edho man\u00e9vru. V\u011bt\u0161inou se ale bude jednat o obrat 90\u00b0 a\u017e 180\u00b0. U n\u011bkter\u00fd p\u0159\u00edstavn\u00edch baz\u00e9n\u016f je p\u0159ist\u00e1vac\u00ed man\u00e9vr spojen\u00fd s couv\u00e1n\u00edm, co\u017e vlastn\u00ed man\u00e9vr je\u0161t\u011b v\u00edce st\u011b\u017euje.<\/p>\n

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B\u011bhem p\u0159ist\u00e1vac\u00edho man\u00e9vru je pot\u0159eba tak\u00e9 po\u010d\u00edtat s \u00fa\u010dinky v\u011btru a proudu vody<\/strong>. V\u00edtr bude hr\u00e1t podstatn\u011bj\u0161\u00ed roli. Rovnob\u011b\u017en\u00e9 p\u0159ibl\u00ed\u017een\u00ed si m\u016f\u017eeme dovolit tehdy, pokud v\u00edtr vane prakticky kolmo k p\u0159ist\u00e1vac\u00edmu molu a s p\u0159ist\u00e1n\u00edm n\u00e1m pom\u016f\u017ee. V opa\u010dn\u00e9m p\u0159\u00edpad\u011b je lep\u0161\u00ed p\u0159ibl\u00ed\u017een\u00ed prov\u00e9st \u0161ikmo, co nejv\u00edce proti v\u011btru. Vane-li v\u00edtr sm\u011brem od<\/strong> p\u0159\u00edstavn\u00edho mola.<\/p>\n

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Popsat v\u0161echny varianty p\u0159ist\u00e1vac\u00edho man\u00e9vru je prakticky nemo\u017en\u00e9 vzhledem ke v\u0161em mo\u017en\u00fdm variant\u00e1m. P\u0159ist\u00e1n\u00ed s vlekem m\u016f\u017ee b\u00fdt st\u00ed\u017eeno je\u0161t\u011b t\u00edm, \u017ee je ur\u010dena p\u0159esn\u00e1 poloha vleku (kam m\u00e1 sm\u011b\u0159ovat p\u0159\u00ed\u010f a z\u00e1\u010f). T\u00edm se m\u016f\u017ee z\u00e1sadn\u011b zm\u011bnit zp\u016fsob p\u0159ibl\u00ed\u017een\u00ed soulod\u00ed k p\u0159\u00edstavu, pop\u0159\u00edpad\u011b proveden\u00ed obrat\u016f nebo za\u0159azen\u00ed couv\u00e1n\u00ed. Ten kdo projektuje tra\u0165 si ur\u010dit\u011b n\u011bjakou tu l\u00edb\u016fstku na kapit\u00e1ny vymysl\u00ed a ti ho pak prokl\u00ednaj\u00ed a\u017e na sam\u00e9 dno \ud83d\ude42<\/p>\n

Na z\u00e1v\u011br jeden p\u0159\u00edmo uk\u00e1zkov\u00fd p\u0159ist\u00e1vac\u00ed man\u00e9vr v pod\u00e1n\u00ed t\u00fdmu LoVe lite.<\/p>\n

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Keba<\/p>\n","protected":false},"excerpt":{"rendered":"

Snad \u017e\u00e1dn\u00fd man\u00e9vr nen\u00ed tak z\u00e1ludn\u00fd jako tento. V\u011bt\u0161inou b\u00fdv\u00e1 za\u0159azen na konec sout\u011b\u017en\u00ed plavby. N\u011bkdy se vyskytne i b\u011bhem plavby. M\u00e1te za sebou n\u011bkolik dlouh\u00fdch minut pln\u00e9ho soust\u0159ed\u011bn\u00ed. \u00dasp\u011b\u0161n\u011b jste zvl\u00e1dli proplout celou tra\u0165 a zb\u00fdv\u00e1 mali\u010dkost – \u00fasp\u011b\u0161n\u011b p\u0159ist\u00e1t. Man\u00e9vr p\u0159i kter\u00e9m m\u016f\u017eete hodn\u011b z\u00edskat, ale taky hodn\u011b ztratit. B\u011bhem p\u0159ist\u00e1n\u00ed tak\u00e9 nej\u010dast\u011bji […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[40],"tags":[143,34],"class_list":["post-3420","post","type-post","status-publish","format-standard","hentry","category-skola","tag-plavba","tag-serial"],"_links":{"self":[{"href":"https:\/\/www.tugtowing.cz\/index.php?rest_route=\/wp\/v2\/posts\/3420","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.tugtowing.cz\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.tugtowing.cz\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.tugtowing.cz\/index.php?rest_route=\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.tugtowing.cz\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=3420"}],"version-history":[{"count":0,"href":"https:\/\/www.tugtowing.cz\/index.php?rest_route=\/wp\/v2\/posts\/3420\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.tugtowing.cz\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=3420"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.tugtowing.cz\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=3420"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.tugtowing.cz\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=3420"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}